5x^2+23x-8120=0

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Solution for 5x^2+23x-8120=0 equation:



5x^2+23x-8120=0
a = 5; b = 23; c = -8120;
Δ = b2-4ac
Δ = 232-4·5·(-8120)
Δ = 162929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{162929}}{2*5}=\frac{-23-\sqrt{162929}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{162929}}{2*5}=\frac{-23+\sqrt{162929}}{10} $

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